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31 changes: 0 additions & 31 deletions python/1512.py

This file was deleted.

11 changes: 11 additions & 0 deletions solutions/1501-1600/1512-number-of-good-pairs/README.md
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# 1512. Number of Good Pairs

[LeetCode problem 1512](https://leetcode.com/problems/number-of-good-pairs/)

- **Difficulty**: Easy
- **Tags**: array, hash-table, math, counting

## Description

Given an array of integers `nums`, return the number of good pairs. A pair
`(i, j)` is good if `nums[i] == nums[j]` and `i < j`.
34 changes: 34 additions & 0 deletions solutions/1501-1600/1512-number-of-good-pairs/solution.cpp
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#include "solution.hpp"

#include <unordered_map>

namespace leetcode::p1512 {

int solve(const std::vector<int>& nums) {
std::unordered_map<int, int> counts;
int result = 0;

for (int value : nums) {
auto& count = counts[value];
result += count;
++count;
}

return result;
}

int solveBruteForce(const std::vector<int>& nums) {
int result = 0;

for (std::size_t i = 0; i < nums.size(); ++i) {
for (std::size_t j = i + 1; j < nums.size(); ++j) {
if (nums[i] == nums[j]) {
++result;
}
}
}

return result;
}

} // namespace leetcode::p1512
14 changes: 14 additions & 0 deletions solutions/1501-1600/1512-number-of-good-pairs/solution.hpp
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#pragma once

#include <vector>

namespace leetcode::p1512 {

// optimized: O(n) time, O(n) space — count occurrences per value, then sum
// count * (count - 1) / 2 for each one.
int solve(const std::vector<int>& nums);

// brute-force: O(n^2) time, O(1) space — check every pair.
int solveBruteForce(const std::vector<int>& nums);

} // namespace leetcode::p1512
15 changes: 15 additions & 0 deletions solutions/1501-1600/1512-number-of-good-pairs/test.cpp
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#include <catch2/catch_test_macros.hpp>

#include "solution.hpp"

TEST_CASE("Problem 1512 - optimized", "[p1512]") {
CHECK(leetcode::p1512::solve({1, 2, 3, 1, 1, 3}) == 4);
CHECK(leetcode::p1512::solve({1, 1, 1, 1}) == 6);
CHECK(leetcode::p1512::solve({1, 2, 3}) == 0);
}

TEST_CASE("Problem 1512 - brute force", "[p1512]") {
CHECK(leetcode::p1512::solveBruteForce({1, 2, 3, 1, 1, 3}) == 4);
CHECK(leetcode::p1512::solveBruteForce({1, 1, 1, 1}) == 6);
CHECK(leetcode::p1512::solveBruteForce({1, 2, 3}) == 0);
}
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